2021 · Q47
If 14sin²θ + 10cos²θ = 11 where 0° < θ < 90°, then what is the value of tanθ + cotθ ?
Elementary MathematicsTrigonometry
- A4/√3
- B2/√3
- C√3
- D2√3
Explanation
14sin²θ + 10cos²θ = 11 gives 14sin²θ + 10(1 − sin²θ) = 11, so 4sin²θ = 1 and sin θ = 1/2 (θ acute). Hence θ = 30°, and tan θ + cot θ = 1/√3 + √3 = 4/√3. This is option (a).