2021 · Q46
What is the minimum value of cos³θ + sec³θ where 0° ≤ θ < 90° ?
Elementary MathematicsTrigonometry
- A0
- B1
- C2
- DNone of the above
Explanation
Put t = cos θ ∈ (0, 1]; then cos³θ + sec³θ = t³ + 1/t³. By AM–GM, t³ + 1/t³ ≥ 2√(t³·1/t³) = 2, with equality at t = 1, i.e. θ = 0°, which is allowed. The minimum value is 2, option (c).