2015 · Q83
In the above figure, ABCD is a parallelogram. P is a point on BC such that PB : PC = 1 : 2 . DP and AB when both* produced meet at Q. If area of triangle BPQ is 20 square unit, the area of triangle DCP is
Elementary MathematicsGeometry: Lines, Angles and Triangles
- A20 square unit
- B30 square unit
- C40 square unit
- DNone of the above
Explanation
With B = (0,0), C = (3,0), P = (1,0), A = (0,h), D = (3,h): Q = (0,-h/2); area BPQ = h/4 = 20 gives h = 80, and area DCP = (1/2)*2*80 = 80, matching none of 20/30/40. Hence option (d).