2015 · Q82
From an external point P tangents PA and PB are drawn to the circle as shown in the above figure. CD is the tangent to the circle at E. If AP = 16 cm, then the perimeter of the triangle PCD is equal to
Elementary MathematicsCircles
- A24 cm
- B28 cm
- C30 cm
- D32 cm
Explanation
CE = CA and DE = DB (tangents from one external point), so the perimeter = (PC + CA) + (PD + DB) = PA + PB = 32 cm. Hence option (d).