2026 · Q21
A shopkeeper sold his goods at the cost price. By using false weights, he gained 11(1/9)%. What weight did he use for 1 kg?
Elementary MathematicsProfit and Loss
- A960 gm
- B950 gm
- C925 gm
- D900 gm
Explanation
A gain of 11(1/9)% equals 100/9%, i.e. a fraction 1/9 of the true weight. If the shopkeeper gives w grams for a kilogram, his gain fraction is (1000 − w)/w = 1/9. Solving 9(1000 − w) = w gives 10w = 9000, so w = 900 g, option D.