Explanation

The sphere (r=3 cm) has volume (4/3)π·27=36π cm³; the wire's cross-section is π(0.25)², giving length 36/0.0625=576. The keyed option is 576 m (C): the original paper evidently means a wire diameter of 0.5 mm (with 0.5 cm the length would be 576 cm, matching no option), but numerically the answer is unambiguously 576, option C. The computation is a straightforward volume-conservation argument; the only subtlety is the unit reading noted above.