2026 · Q4
If 1/x = 1/p + 1/q, then what is [pq/(p^2 - q^2)] x [(x + p)/(x - p) - (x + q)/(x - q)] equal to?
Elementary MathematicsAlgebra
- A-2
- B-1
- C1
- D2
Explanation
From 1/x=1/p+1/q=(p+q)/pq we get x=pq/(p+q). Substituting, (x+p)/(x−p)=−(p+2q)/p and (x+q)/(x−q)=−(2p+q)/q, so their difference is −2q/p+2p/q=2(p²−q²)/pq. Multiplying by the prefactor pq/(p²−q²) cancels everything to leave 2, option D. The trap is mis-simplifying (x+p)/(x−p) by forgetting the common denominator.