Explanation

Put a=log2, b=log3, c=log5; then p=4a+c, q=2b+c, r=3a+3b. From r, a+b=r/3, and eliminating a,b,c from the three equations gives 7a+b=p−q+r. Since log384=log(2^7·3)=7a+b, we get log10(384)=p−q+r, option B.