2025 · Q83
what is the Hcf of the polynomials x⁸ + x⁴ + 1 and x⁴ + x² + 1 ?
Elementary MathematicsHCF and LCM
- A1
- Bx⁴ - x² + 1
- Cx⁴ + x² + 1
- Dx⁴ - x² - 1
Explanation
x⁸ + x⁴ + 1 = (x⁴ + x² + 1)(x⁴ − x² + 1) = q·(x⁴−x²+1), so the HCF of p and q is q = x⁴ + x² + 1, option (c).