2025 · Q77
If p = 0.09̅, then what is the value of 70p² + 43p - 5:
Elementary MathematicsNumber System
- A-1
- B0
- C1
- D10
Explanation
The recurring decimal 0.0999... equals exactly 0.1, since 0.0p9-bar = 1/10. Substituting p = 0.1: 70*(0.01) + 43*(0.1) - 5 = 0.7 + 4.3 - 5 = 0. Hence the value is 0, option (b).