2025 · Q66
Consider the following for the next two (02) items that follow: ABC is a triangle right-angled at A. Further AB = 8 cm and BC = 10 cm. D is the point on BC such that AD is perpendicular to BC. What is ratio of area of triangle ADC to area of triangle ADB?
Elementary MathematicsGeometry: Lines, Angles and Triangles
- A7 : 15
- B9 : 16
- C2 : 3
- D3 : 4
Explanation
BD = AB²/BC = 64/10 = 6.4 cm and CD = AC²/BC = 36/10 = 3.6 cm. The areas of ADC and ADB share altitude AD, so their ratio is CD:BD = 3.6:6.4 = 9:16, option (b).