2025 · Q24
The minimum power required to lift a mass of 50 kg up to a vertical distance of 8 m in 10 s is:
(Take g = 10 m/s2)
General KnowledgePhysics
- A400 W
- B40 W
- C50 W
- D500 W
Explanation
The work done in lifting the boy is W = mgh = 50 x 10 x 8 = 4000 J. Power is work divided by time, so P = 4000/10 = 400 W. The average power developed is therefore 400 watts.