Explanation

The options show this is sin²θcos²θ(sec²θ + cosec²θ) = 1 (the stored 'sin2θ' transcribes sin²θ, as in Q11). Indeed sin²θcos²θ·sec²θ = sin²θ and sin²θcos²θ·cosec²θ = cos²θ, whose sum is sin²θ+cos²θ = 1. Hence the value is 1 — option B.