2024 · Q41
In a right - angled triangle ABC, AB = 15 cm, BC 20 cm and AC = 25 cm. Further, BP is the perpendicular on AC. What is the difference in the area of triangles PAB and PCB ?
Elementary MathematicsGeometry: Lines, Angles and Triangles
- A40 square cm
- B42 square cm
- C45 square cm
- D48 square cm
Explanation
Area of ABC is 150, so the altitude BP = 2 × 150/25 = 12 cm. Then |area(PAB) − area(PCB)| = (1/2) × 12 × |AP − PC|. With AP = 16 and PC = 9, this is 6 × 7 = 42 sq cm, option (b).