2024 · Q18
If n is a natural number, then what is the sum of all distinct remainders of 4ⁿ + 6ⁿ + 9ⁿ + 11ⁿ when divided by 10 for various values of n?
Elementary MathematicsNumber System
- A3
- B4
- C6
- D7
Explanation
For odd n the sum is ≡ 4 + 6 + 9 + 1 = 20 ≡ 0 (mod 10). For even n it is ≡ 6 + 6 + 1 + 1 = 14 ≡ 4 (mod 10). The distinct remainders are 0 and 4, summing to 4, option (b).