2021 · Q58
What is (2sin³θ − sinθ)/(cosθ − 2cos³θ), (0° < θ < 90°) equal to ?
Elementary MathematicsTrigonometry
- Asinθ
- Bcosθ
- Ctanθ
- Dcotθ
Explanation
Factor: numerator = sinθ(2sin²θ − 1) and denominator = −cosθ(2cos²θ − 1). Since 2sin²θ − 1 = −cos2θ and 2cos²θ − 1 = cos2θ, the ratio is sinθ(−cos2θ)/(−cosθ·cos2θ) = tanθ. This is option (c).