2021 · Q90
What is 1/[(a−b)(b−c)] + 1/[(b−c)(c−a)] + 1/[(c−a)(a−b)] equal to?
Elementary MathematicsAlgebra
- Aa + b
- B3
- Cab + bc + ca
- D0
Explanation
Over the common denominator (a−b)(b−c)(c−a), the numerator is (c−a) + (a−b) + (b−c) = 0. So the whole expression equals 0. Hence option D.