2021 · Q25
If the perimeter of a semicircular park is 360 m, then what is its area? (Take π = 22/7)
Elementary MathematicsMensuration
- A3850 m²
- B7700 m²
- C11550 m²
- D15400 m²
Explanation
Perimeter of the semicircular park: πr + 2r = 360, i.e. r(22/7 + 2) = 360, so r = 360·7/36 = 70 m. Its area is ½πr² = ½·(22/7)·70² = 7700 m². Hence option B.