2019 · Q68
A bucket is in the form of a truncated cone. The diameters of the base and top of the bucket are 6 cm and 12 cm respectively. If the height of the bucket is 7 cm, what is the capacity of the bucket?
Elementary MathematicsMensuration
- A535 cm³
- B462 cm³
- C234 cm³
- D166 cm³
Explanation
Frustum volume = (.pi.h/3)(R^2+Rr+r^2) with R = 6, r = 3, h = 7: (7.pi/3)x63 = 147.pi = 461.8, i.e. 462 cm^3.