2019 · Q95
Consider the following for the next three (03) items:
ABCD is a quadrilateral with AB = 9 cm, BC = 40 cm, CD = 28 cm, DA = 15 cm and angle ABC is a right-angle.
What is the area of quadrilateral ABCD?
Elementary MathematicsMensuration
- A300 cm²
- B306 cm²
- C312 cm²
- D316 cm²
Explanation
Area ABC = 9×40/2 = 180. For ADC (sides 15, 28, 41): s = 42, area = √(42×27×14×1) = 126. Quadrilateral = 180 + 126 = 306 cm^2.