2019 · Q13
It is given that log₁₀2 = 0.301 and log₁₀3 = 0.477. How many digits are there in (108)¹⁰?
Elementary MathematicsAlgebra
- A19
- B20
- C21
- D22
Explanation
Number of digits = floor(10·log10 108) + 1. log10 108 = log10(2^2·3^3) = 2(0.301) + 3(0.477) = 0.602 + 1.431 = 2.033. 10 × 2.033 = 20.33, so (108)^10 has 21 digits.