2018 · Q46
There are n zeros appearing immediately after the decimal point in the value of (0.2)²5} . It is given that the value of ₁0} 2 = 0.30103. The value of n is
Elementary MathematicsNumber System
- A25
- B19
- C18
- D17
Explanation
log_10((0.2)^25) = 25(log_10 2 - 1) = 25 x (-0.69897) = -17.474, so (0.2)^25 = 3.35... x 10^(-18). There are therefore 17 zeros immediately after the decimal point. Hence option D.