2018 · Q28
A train 100 m long passes a platform 100 m long in 10 seconds. The speed of the train is
Elementary MathematicsTime, Speed and Distance
- A36 kmph
- B45 kmph
- C54 kmph
- D72 kmph
Explanation
Total distance = train length + platform length = 100 + 100 = 200 m, covered in 10 s. Speed = 200/10 = 20 m/s = 20 x 3.6 = 72 kmph. Hence option D.