2017 · Q98
In the figure given below, M is the mid-point of AB and ∠ DAB = ∠ CBA and ∠ AMC = ∠ BMD. Then the △ ADM is congruent to the △ BCM by
Elementary MathematicsGeometry: Lines, Angles and Triangles
- ASAS rule
- BSSS rule
- CASA rule
- DAAA rule
Explanation
∠DAB = ∠CBA (alternate interior) gives AD ∥ BC. With M the mid-point of AB: AM = BM, ∠DAM = ∠CBM, and ∠AMD = ∠BMC (vertically opposite). Hence ΔADM ≅ ΔBCM by ASA: option C.