2016 · Q4
If x² = y + z, y² = z + x and z² = x + y, then what is the value of 1/(x+1) + 1/(y+1) + 1/(z+1)?
Elementary MathematicsAlgebra
- A-1
- B1
- C2
- D4
Explanation
From x² = y+z, adding x to both sides gives x(x+1) = x+y+z; call this sum S. Hence 1/(x+1) = x/S, and similarly 1/(y+1) = y/S and 1/(z+1) = z/S. Adding gives (x+y+z)/S = 1 (option B), valid as long as none of x, y, z equals −1.