2016 · Q96
The value of (1/5)log₁₀3125 − 4log₁₀2 + log₁₀32 is
Elementary MathematicsAlgebra
- A0
- B1
- C2
- D3
Explanation
Since 3125 = 5⁵, (1/5)log₁₀3125 = log₁₀5. Also −4log₁₀2 = −log₁₀16. The expression becomes log₁₀5 − log₁₀16 + log₁₀32 = log₁₀(5·32/16). This equals log₁₀10 = 1, option B.