2016 · Q76
If 61/19=3+1/(x+1/(y+1/z)) where x, y and z are natural numbers, then what is z equal to?
Elementary MathematicsNumber System
- A1
- B2
- C3
- D4
Explanation
Compute 61/19 = 3+4/19 = 3+1/(4+3/4) = 3+1/(4+1/(1+1/3)). Matching against 3+1/(x+1/(y+1/z)) gives x = 4, y = 1 and z = 3. Hence z = 3, option C.