2016 · Q67
In a triangle ABC if A-B=π/2, then C+2B is equal to
Elementary MathematicsTrigonometry
- A2π/3
- B3π/4
- Cπ
- Dπ/2
Explanation
We have A−B = π/2 and A+B+C = π. Substituting A = B+π/2 into the second gives (B+π/2)+B+C = π. Simplifying yields C+2B = π/2, option D.