2016 · Q42
There are three brothers. The sums of ages of two of them at a time are 4 years, 6 years and 8 years. The age difference between the eldest and the youngest is
Elementary MathematicsRatio and Proportion
- A3 years
- B4 years
- C5 years
- D6 years
Explanation
With pairwise sums 4, 6, 8, twice the total is 18, so the ages sum to 9. The three ages are 9−6 = 3, 9−8 = 1 and 9−4 = 5. Eldest minus youngest = 5−1 = 4 years, option B.