2016 · Q30
In a circle of radius 2 units, a diameter AB intersects a chord of length 2 units perpendicularly at P. If AP > BP, then AP is equal to
Elementary MathematicsCircles
- A(2+√(5)) units
- B(2+√(3)) units
- C(2+√(2)) units
- D3 units
Explanation
The half-chord is 1 and the radius is 2, so the distance from the centre O to the chord is √(4−1) = √3. Since AP > BP, P lies on the B-side of O. Hence AP = AO+OP = 2+√3, option B.