Explanation

This tests standard trigonometric values. cot(π/4) = 1, so 32cot²(π/4) = 32; sec(π/3) = 2, so 8sec²(π/3) = 32; cos(π/6) = √3/2, so 8cos³(π/6) = 8 × 3√3/8 = 3√3. The total is 32 - 32 + 3√3 = 3√3. Option (c) 3 is the trap from dropping the √3 in the last term. Hence option (d).