2015 · Q30
If a:b=3:5 and b:c=7:8, then 2a:3b:7c is equal to
Elementary MathematicsAlgebra
- A42:105:320
- B15:21:35
- C6:15:40
- D30:21:350
Explanation
This tests combining two ratios through their common term. From a:b = 3:5 = 21:35 and b:c = 7:8 = 35:40, the combined ratio is a:b:c = 21:35:40. Then 2a:3b:7c = 42:105:280, and dividing by the common factor 7 gives 6:15:40. The trap is option (a) 42:105:320, which comes from miscomputing 7c; the careful step is fixing b at its common value 35 before scaling. Hence option (c).