2015 · Q77
Two circles, each of radius r, with centres P and Q, are such that each circle passes through the centre of the other circle. Then the area common to the circles is less than one-third of the sum of the areas of the two circles by
Elementary MathematicsCircles
- A√3r²/4
- B√3r²/3
- C√3r²/2
- D√3r²
Explanation
Common area = 2r²(π/3 − √3/4); one-third of the sum of the areas is 2πr²/3; the difference is 2πr²/3 − 2r²(π/3 − √3/4) = √3r²/2 (option C).