2015 · Q55
AD is the diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, the distance of AB from the centre of the circle is
Elementary MathematicsCircles
- A17 cm
- B15 cm
- C13 cm
- D8 cm
Explanation
The perpendicular from the centre bisects the chord: half-chord 15 cm, radius 17 cm, so distance = √(17²−15²) = √64 = 8 cm (option D).