2014 · Q24
How many pairs of X and Y are possible in the number 763X4Y2, if the number is divisible by 9?
Elementary MathematicsNumber System
- A8
- B9
- C10
- D11
Explanation
Digit sum 22 + X + Y must be a multiple of 9, so X + Y = 5 (6 pairs) or 14 (5 pairs): 11 pairs.