2014 · Q56
In a right-angled triangle ABC, right-angled at B, if cos A = 4/5, then what is sin C equal to?
Elementary MathematicsTrigonometry
- A3/5
- B4/5
- C3/4
- D2/5
Explanation
C = 90° - A, so sin C = sin(90° - A) = cos A = 4/5.
In a right-angled triangle ABC, right-angled at B, if cos A = 4/5, then what is sin C equal to?
Explanation
C = 90° - A, so sin C = sin(90° - A) = cos A = 4/5.