2013 · Q94
What is [(1+secθ−tanθ)cosθ]/[(1+secθ+tanθ)(1−sinθ)] equal to?
Elementary MathematicsTrigonometry
- A1
- B2
- Ctanθ
- Dcotθ
Explanation
(1+sec−tan)/(1+sec+tan)=sec−tan=(1−sin)/cos → expression=1. Verified via allen.in (fraction form). Answer A.
What is [(1+secθ−tanθ)cosθ]/[(1+secθ+tanθ)(1−sinθ)] equal to?
Explanation
(1+sec−tan)/(1+sec+tan)=sec−tan=(1−sin)/cos → expression=1. Verified via allen.in (fraction form). Answer A.