2013 · Q89
If triangle ABC is right-angled at C, then cos(A+B)+sin(A+B) equals
Elementary MathematicsTrigonometry
- A0
- B1/2
- C1
- D2
Explanation
A+B=90°; cos90+sin90=1. Answer C.
If triangle ABC is right-angled at C, then cos(A+B)+sin(A+B) equals
Explanation
A+B=90°; cos90+sin90=1. Answer C.