2012 · Q33
If (x - 6) is the HCF of x^2 - 2x - 24 and x^2 - kx - 6, then what is the value of k?
Elementary MathematicsAlgebra
- A3
- B5
- C6
- D8
Explanation
x^2-2x-24 = (x-6)(x+4); for (x-6) to divide x^2-kx-6, 36-6k-6 = 0, so k = 5.
If (x - 6) is the HCF of x^2 - 2x - 24 and x^2 - kx - 6, then what is the value of k?
Explanation
x^2-2x-24 = (x-6)(x+4); for (x-6) to divide x^2-kx-6, 36-6k-6 = 0, so k = 5.