2010 · Q99
(For the next three questions to follow):
Let ABCD be a quadrilateral. Let the diagonals AC and BD meet at O. Let the perpendicular drawn from A to CD meet CD at E. Further, AO:OC = BO:OD, AB = 30 cm, CD = 40 cm and the area of the quadrilateral ABCD is 1050 cm².
What is the area of the triangle ADC equal to ?
Elementary MathematicsMensuration
- A300 cm²
- B450 cm²
- C600 cm²
- DNone of the above
Explanation
Area(ΔADC)=½×40×30=600 cm².