2010 · Q14
What is the value of (1/3)log₁₀125 – 2log₁₀4 + log₁₀32 + log₁₀1 ?
Elementary MathematicsAlgebra
- A0
- B1/3
- C1
- D2/3
Explanation
(1/3)log125-log16+log32 = log(5×32/16)=log10=1.
What is the value of (1/3)log₁₀125 – 2log₁₀4 + log₁₀32 + log₁₀1 ?
Explanation
(1/3)log125-log16+log32 = log(5×32/16)=log10=1.