2010 · Q1
What can be said about the expansion of 2^12n – 6^4n, where n is a positive integer ?
Elementary MathematicsNumber System
- ALast digit is 4
- BLast digit is 8
- CLast digit is 2
- DLast two digits are zero
Explanation
2^12n-6^4n = (4096)^n-(1296)^n is divisible by 4096-1296=2800, so its last two digits are 00.