2017 · Q80
One year ago, a father was four times as old as his son. After six years his age exceeds twice his son's age by 9 years. The ratio of their present age is
general-mental-abilityquantitative-aptitude
- A9:2
- B11:3
- C12:5
- D13:4
Explanation
Let the present ages be f (father) and s (son): f − 1 = 4(s − 1) and f + 6 = 2(s + 6) + 9. Solving gives s = 9 and f = 33, a ratio of 11:3. Hence (B).